Base | Representation |
---|---|
bin | 11101001000101000011… |
… | …000101001111110101111 |
3 | 21002101212001011112002222 |
4 | 131020220120221332233 |
5 | 230300331332440413 |
6 | 4131433351505555 |
7 | 264435463600046 |
oct | 35105030517657 |
9 | 7071761145088 |
10 | 2002132311983 |
11 | 7021105493a1 |
12 | 28403a0882bb |
13 | 116a5325663b |
14 | 6cc91b4b55d |
15 | 371302c8b08 |
hex | 1d228629faf |
2002132311983 has 2 divisors, whose sum is σ = 2002132311984. Its totient is φ = 2002132311982.
The previous prime is 2002132311961. The next prime is 2002132312009. The reversal of 2002132311983 is 3891132312002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2002132311983 - 214 = 2002132295599 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2002132311923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001066155991 + 1001066155992.
It is an arithmetic number, because the mean of its divisors is an integer number (1001066155992).
Almost surely, 22002132311983 is an apocalyptic number.
2002132311983 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002132311983 is an equidigital number, since it uses as much as digits as its factorization.
2002132311983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 35.
Adding to 2002132311983 its reverse (3891132312002), we get a palindrome (5893264623985).
The spelling of 2002132311983 in words is "two trillion, two billion, one hundred thirty-two million, three hundred eleven thousand, nine hundred eighty-three".
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