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2002132313201 = 9997120027131
BaseRepresentation
bin11101001000101000011…
…000101010010001110001
321002101212001011120210002
4131020220120222101301
5230300331333010301
64131433351515345
7264435463603436
oct35105030522161
97071761146702
102002132313201
1170211054a2a9
1228403a088b55
13116a53257067
146cc91b4bb8d
15371302c916b
hex1d22862a471

2002132313201 has 4 divisors (see below), whose sum is σ = 2002152440304. Its totient is φ = 2002112186100.

The previous prime is 2002132313197. The next prime is 2002132313239. The reversal of 2002132313201 is 1023132312002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2002132313201 - 22 = 2002132313197 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2002132313801) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9913595 + ... + 10113536.

It is an arithmetic number, because the mean of its divisors is an integer number (500538110076).

Almost surely, 22002132313201 is an apocalyptic number.

It is an amenable number.

2002132313201 is a deficient number, since it is larger than the sum of its proper divisors (20127103).

2002132313201 is an equidigital number, since it uses as much as digits as its factorization.

2002132313201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20127102.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 2002132313201 its reverse (1023132312002), we get a palindrome (3025264625203).

The spelling of 2002132313201 in words is "two trillion, two billion, one hundred thirty-two million, three hundred thirteen thousand, two hundred one".

Divisors: 1 99971 20027131 2002132313201