Base | Representation |
---|---|
bin | 10010101001010111… |
… | …010111100010010011 |
3 | 1220200022200200021012 |
4 | 102221113113202103 |
5 | 312000431010103 |
6 | 13110410521135 |
7 | 1306101422324 |
oct | 225127274223 |
9 | 56608620235 |
10 | 20021344403 |
11 | 8544588425 |
12 | 3a691361ab |
13 | 1b70c3bc68 |
14 | d7d08044b |
15 | 7c2a852d8 |
hex | 4a95d7893 |
20021344403 has 2 divisors, whose sum is σ = 20021344404. Its totient is φ = 20021344402.
The previous prime is 20021344379. The next prime is 20021344471. The reversal of 20021344403 is 30444312002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20021344403 - 26 = 20021344339 is a prime.
It is not a weakly prime, because it can be changed into another prime (20021344493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10010672201 + 10010672202.
It is an arithmetic number, because the mean of its divisors is an integer number (10010672202).
Almost surely, 220021344403 is an apocalyptic number.
20021344403 is a deficient number, since it is larger than the sum of its proper divisors (1).
20021344403 is an equidigital number, since it uses as much as digits as its factorization.
20021344403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 23.
Adding to 20021344403 its reverse (30444312002), we get a palindrome (50465656405).
The spelling of 20021344403 in words is "twenty billion, twenty-one million, three hundred forty-four thousand, four hundred three".
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