Base | Representation |
---|---|
bin | 11101001000101001100… |
… | …001010010010011110111 |
3 | 21002101220100222211110212 |
4 | 131020221201102103313 |
5 | 230300401221222133 |
6 | 4131435311540035 |
7 | 264436114456010 |
oct | 35105141222367 |
9 | 7071810884425 |
10 | 2002151351543 |
11 | 702120273072 |
12 | 28404452a61b |
13 | 116a57191855 |
14 | 6cc944a6007 |
15 | 37131cda148 |
hex | 1d2298524f7 |
2002151351543 has 4 divisors (see below), whose sum is σ = 2288172973200. Its totient is φ = 1716129729888.
The previous prime is 2002151351527. The next prime is 2002151351579. The reversal of 2002151351543 is 3451531512002.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 2002151351543 - 24 = 2002151351527 is a prime.
It is a super-2 number, since 2×20021513515432 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2002151351443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 143010810818 + ... + 143010810831.
It is an arithmetic number, because the mean of its divisors is an integer number (572043243300).
Almost surely, 22002151351543 is an apocalyptic number.
2002151351543 is a deficient number, since it is larger than the sum of its proper divisors (286021621657).
2002151351543 is an equidigital number, since it uses as much as digits as its factorization.
2002151351543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 286021621656.
The product of its (nonzero) digits is 18000, while the sum is 32.
Adding to 2002151351543 its reverse (3451531512002), we get a palindrome (5453682863545).
The spelling of 2002151351543 in words is "two trillion, two billion, one hundred fifty-one million, three hundred fifty-one thousand, five hundred forty-three".
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