Base | Representation |
---|---|
bin | 101101100001100101011010… |
… | …101000111010011010111010 |
3 | 222020220211211211100120021122 |
4 | 231201211122220322122322 |
5 | 202220401040321041442 |
6 | 1545455445303105242 |
7 | 60113263345026341 |
oct | 5541453250723272 |
9 | 866824754316248 |
10 | 200220011112122 |
11 | 58883914603241 |
12 | 1a557b90742222 |
13 | 87948873767b1 |
14 | 37629b3680b58 |
15 | 18232ae226dd2 |
hex | b6195aa3a6ba |
200220011112122 has 4 divisors (see below), whose sum is σ = 300330016668186. Its totient is φ = 100110005556060.
The previous prime is 200220011112103. The next prime is 200220011112133. The reversal of 200220011112122 is 221211110022002.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 125642779484401 + 74577231627721 = 11209049^2 + 8635811^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 200220011112122.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055002778029 + ... + 50055002778032.
Almost surely, 2200220011112122 is an apocalyptic number.
200220011112122 is a deficient number, since it is larger than the sum of its proper divisors (100110005556064).
200220011112122 is a wasteful number, since it uses less digits than its factorization.
200220011112122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 100110005556063.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 200220011112122 its reverse (221211110022002), we get a palindrome (421431121134124).
The spelling of 200220011112122 in words is "two hundred trillion, two hundred twenty billion, eleven million, one hundred twelve thousand, one hundred twenty-two".
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