Search a number
-
+
200220011112122 = 2100110005556061
BaseRepresentation
bin101101100001100101011010…
…101000111010011010111010
3222020220211211211100120021122
4231201211122220322122322
5202220401040321041442
61545455445303105242
760113263345026341
oct5541453250723272
9866824754316248
10200220011112122
1158883914603241
121a557b90742222
1387948873767b1
1437629b3680b58
1518232ae226dd2
hexb6195aa3a6ba

200220011112122 has 4 divisors (see below), whose sum is σ = 300330016668186. Its totient is φ = 100110005556060.

The previous prime is 200220011112103. The next prime is 200220011112133. The reversal of 200220011112122 is 221211110022002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 125642779484401 + 74577231627721 = 11209049^2 + 8635811^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 200220011112122.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055002778029 + ... + 50055002778032.

Almost surely, 2200220011112122 is an apocalyptic number.

200220011112122 is a deficient number, since it is larger than the sum of its proper divisors (100110005556064).

200220011112122 is a wasteful number, since it uses less digits than its factorization.

200220011112122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100110005556063.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 200220011112122 its reverse (221211110022002), we get a palindrome (421431121134124).

The spelling of 200220011112122 in words is "two hundred trillion, two hundred twenty billion, eleven million, one hundred twelve thousand, one hundred twenty-two".

Divisors: 1 2 100110005556061 200220011112122