Base | Representation |
---|---|
bin | 1001000110101101111001… |
… | …11011001111011100000111 |
3 | 2121220002022110022210012212 |
4 | 10203112330323033130013 |
5 | 10111020040111303444 |
6 | 110325552504134035 |
7 | 4134354061524656 |
oct | 443267473173407 |
9 | 77802273283185 |
10 | 20022012212999 |
11 | 641a318a15505 |
12 | 22b449746731b |
13 | b230b5820944 |
14 | 4d30db89b19d |
15 | 24ac425c819e |
hex | 1235bcecf707 |
20022012212999 has 2 divisors, whose sum is σ = 20022012213000. Its totient is φ = 20022012212998.
The previous prime is 20022012212971. The next prime is 20022012213019. The reversal of 20022012212999 is 99921221022002.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20022012212999 is a prime.
It is a super-2 number, since 2×200220122129992 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20022012212299) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10011006106499 + 10011006106500.
It is an arithmetic number, because the mean of its divisors is an integer number (10011006106500).
Almost surely, 220022012212999 is an apocalyptic number.
20022012212999 is a deficient number, since it is larger than the sum of its proper divisors (1).
20022012212999 is an equidigital number, since it uses as much as digits as its factorization.
20022012212999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46656, while the sum is 41.
The spelling of 20022012212999 in words is "twenty trillion, twenty-two billion, twelve million, two hundred twelve thousand, nine hundred ninety-nine".
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