Base | Representation |
---|---|
bin | 1011101001111000001… |
… | …1001111011111111111 |
3 | 201010210200112020120111 |
4 | 2322132003033133333 |
5 | 11240022324130123 |
6 | 231551352330451 |
7 | 20315433105046 |
oct | 2723603173777 |
9 | 633720466514 |
10 | 200220145663 |
11 | 77a0506396a |
12 | 329793a3a27 |
13 | 15b5ab0ac95 |
14 | 999542955d |
15 | 531c95c90d |
hex | 2e9e0cf7ff |
200220145663 has 2 divisors, whose sum is σ = 200220145664. Its totient is φ = 200220145662.
The previous prime is 200220145639. The next prime is 200220145681. The reversal of 200220145663 is 366541022002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200220145663 - 213 = 200220137471 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200220145603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100110072831 + 100110072832.
It is an arithmetic number, because the mean of its divisors is an integer number (100110072832).
Almost surely, 2200220145663 is an apocalyptic number.
200220145663 is a deficient number, since it is larger than the sum of its proper divisors (1).
200220145663 is an equidigital number, since it uses as much as digits as its factorization.
200220145663 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 200220145663 its reverse (366541022002), we get a palindrome (566761167665).
The spelling of 200220145663 in words is "two hundred billion, two hundred twenty million, one hundred forty-five thousand, six hundred sixty-three".
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