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2002213310303 = 4148834470983
BaseRepresentation
bin11101001000101101001…
…101101000111101011111
321002102001200120122220202
4131020231031220331133
5230301013101412203
64131445403534115
7264440466221543
oct35105515507537
97072050518822
102002213310303
11702152241658
1228406122a33b
13116a66c7623b
146cc9c7d3a23
1537137478388
hex1d22d368f5f

2002213310303 has 4 divisors (see below), whose sum is σ = 2051047781328. Its totient is φ = 1953378839280.

The previous prime is 2002213310173. The next prime is 2002213310359. The reversal of 2002213310303 is 3030133122002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2002213310303 - 212 = 2002213306207 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2002213312303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24417235451 + ... + 24417235532.

It is an arithmetic number, because the mean of its divisors is an integer number (512761945332).

Almost surely, 22002213310303 is an apocalyptic number.

2002213310303 is a deficient number, since it is larger than the sum of its proper divisors (48834471025).

2002213310303 is an equidigital number, since it uses as much as digits as its factorization.

2002213310303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48834471024.

The product of its (nonzero) digits is 648, while the sum is 20.

Adding to 2002213310303 its reverse (3030133122002), we get a palindrome (5032346432305).

The spelling of 2002213310303 in words is "two trillion, two billion, two hundred thirteen million, three hundred ten thousand, three hundred three".

Divisors: 1 41 48834470983 2002213310303