Base | Representation |
---|---|
bin | 11101001000101101101… |
… | …111001101010110110011 |
3 | 21002102002022010202000022 |
4 | 131020231233031112303 |
5 | 230301022330011011 |
6 | 4131450320314055 |
7 | 264440634062165 |
oct | 35105557152663 |
9 | 7072068122008 |
10 | 2002222110131 |
11 | 702157202041 |
12 | 28406417292b |
13 | 116a68a37739 |
14 | 6cc9da44935 |
15 | 371381158db |
hex | 1d22dbcd5b3 |
2002222110131 has 2 divisors, whose sum is σ = 2002222110132. Its totient is φ = 2002222110130.
The previous prime is 2002222110113. The next prime is 2002222110169. The reversal of 2002222110131 is 1310112222002.
Together with previous prime (2002222110113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2002222110131 - 222 = 2002217915827 is a prime.
It is a super-2 number, since 2×20022221101312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2002222130131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001111055065 + 1001111055066.
It is an arithmetic number, because the mean of its divisors is an integer number (1001111055066).
Almost surely, 22002222110131 is an apocalyptic number.
2002222110131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002222110131 is an equidigital number, since it uses as much as digits as its factorization.
2002222110131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 2002222110131 its reverse (1310112222002), we get a palindrome (3312334332133).
The spelling of 2002222110131 in words is "two trillion, two billion, two hundred twenty-two million, one hundred ten thousand, one hundred thirty-one".
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