Base | Representation |
---|---|
bin | 11101001000110011100… |
… | …101011001011001100111 |
3 | 21002102100010201021211021 |
4 | 131020303211121121213 |
5 | 230301222432420234 |
6 | 4131504142552011 |
7 | 264443234614264 |
oct | 35106345313147 |
9 | 7072303637737 |
10 | 2002320201319 |
11 | 7021a760a439 |
12 | 284090b98607 |
13 | 116a83160469 |
14 | 6ccaca9a26b |
15 | 37141a3e9b4 |
hex | 1d233959667 |
2002320201319 has 2 divisors, whose sum is σ = 2002320201320. Its totient is φ = 2002320201318.
The previous prime is 2002320201209. The next prime is 2002320201331. The reversal of 2002320201319 is 9131020232002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2002320201319 - 213 = 2002320193127 is a prime.
It is a super-2 number, since 2×20023202013192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2002320201293 and 2002320201302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2002320201379) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001160100659 + 1001160100660.
It is an arithmetic number, because the mean of its divisors is an integer number (1001160100660).
Almost surely, 22002320201319 is an apocalyptic number.
2002320201319 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002320201319 is an equidigital number, since it uses as much as digits as its factorization.
2002320201319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
The spelling of 2002320201319 in words is "two trillion, two billion, three hundred twenty million, two hundred one thousand, three hundred nineteen".
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