Base | Representation |
---|---|
bin | 1001000110110000001000… |
… | …11001001000100001011011 |
3 | 2121220012102000111020010221 |
4 | 10203120010121020201123 |
5 | 10111030014033400243 |
6 | 110330311455220511 |
7 | 4134425561154136 |
oct | 443300431104133 |
9 | 77805360436127 |
10 | 20023211231323 |
11 | 641a883810743 |
12 | 22b4770b17737 |
13 | b23247060341 |
14 | 4d31b2c1321d |
15 | 24acb29bcbed |
hex | 12360464885b |
20023211231323 has 4 divisors (see below), whose sum is σ = 20039398145440. Its totient is φ = 20007024317208.
The previous prime is 20023211231299. The next prime is 20023211231327. The reversal of 20023211231323 is 32313211232002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20023211231323 - 217 = 20023211100251 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20023211231327) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8093455203 + ... + 8093457676.
It is an arithmetic number, because the mean of its divisors is an integer number (5009849536360).
Almost surely, 220023211231323 is an apocalyptic number.
20023211231323 is a deficient number, since it is larger than the sum of its proper divisors (16186914117).
20023211231323 is a wasteful number, since it uses less digits than its factorization.
20023211231323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16186914116.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 20023211231323 its reverse (32313211232002), we get a palindrome (52336422463325).
The spelling of 20023211231323 in words is "twenty trillion, twenty-three billion, two hundred eleven million, two hundred thirty-one thousand, three hundred twenty-three".
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