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2002323000131 = 3116438337621
BaseRepresentation
bin11101001000110011110…
…000000100101101000011
321002102100022222111001222
4131020303300010231003
5230301224142001011
64131504322545255
7264443300452136
oct35106360045503
97072308874058
102002323000131
117021a9151203
12284091b0822b
13116a8390036c
146ccad1c821d
1537141de3ddb
hex1d233c04b43

2002323000131 has 4 divisors (see below), whose sum is σ = 2008761338064. Its totient is φ = 1995884662200.

The previous prime is 2002323000101. The next prime is 2002323000143. The reversal of 2002323000131 is 1310003232002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2002323000131 - 210 = 2002322999107 is a prime.

It is a super-2 number, since 2×20023230001312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2002323000101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3219168500 + ... + 3219169121.

It is an arithmetic number, because the mean of its divisors is an integer number (502190334516).

Almost surely, 22002323000131 is an apocalyptic number.

2002323000131 is a deficient number, since it is larger than the sum of its proper divisors (6438337933).

2002323000131 is an equidigital number, since it uses as much as digits as its factorization.

2002323000131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6438337932.

The product of its (nonzero) digits is 216, while the sum is 17.

Adding to 2002323000131 its reverse (1310003232002), we get a palindrome (3312326232133).

The spelling of 2002323000131 in words is "two trillion, two billion, three hundred twenty-three million, one hundred thirty-one", and thus it is an aban number.

Divisors: 1 311 6438337621 2002323000131