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2002331211103 = 113127509274117
BaseRepresentation
bin11101001000110100001…
…111011001010101011111
321002102100220102122102001
4131020310033121111133
5230301233242223403
64131505214543131
7264443430320626
oct35106417312537
97072326378361
102002331211103
1170220284a233
12284094807aa7
13116a85516822
146ccb03246bd
15371429b6c1d
hex1d2343d955f

2002331211103 has 16 divisors (see below), whose sum is σ = 2039964226560. Its totient is φ = 1965109095936.

The previous prime is 2002331211091. The next prime is 2002331211137. The reversal of 2002331211103 is 3011121332002.

It is not a de Polignac number, because 2002331211103 - 25 = 2002331211071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2002331211143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7167601 + ... + 7441717.

It is an arithmetic number, because the mean of its divisors is an integer number (127497764160).

Almost surely, 22002331211103 is an apocalyptic number.

2002331211103 is a deficient number, since it is larger than the sum of its proper divisors (37633015457).

2002331211103 is a wasteful number, since it uses less digits than its factorization.

2002331211103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 274866.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 2002331211103 its reverse (3011121332002), we get a palindrome (5013452543105).

The spelling of 2002331211103 in words is "two trillion, two billion, three hundred thirty-one million, two hundred eleven thousand, one hundred three".

Divisors: 1 113 127 509 14351 57517 64643 274117 7304659 30975221 34812859 139525553 3933853067 15766387489 17719745231 2002331211103