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200234121420022 = 2100117060710011
BaseRepresentation
bin101101100001110010100011…
…101011011101110011110110
3222020222012021012101110211221
4231201302203223131303312
5202221113440040420042
61545510141400020554
760114303122461264
oct5541624353356366
9866865235343757
10200234121420022
11588898a54a3428
121a55a86a16175a
138795cc5797c01
14376355166d434
151823837d98d67
hexb61ca3addcf6

200234121420022 has 4 divisors (see below), whose sum is σ = 300351182130036. Its totient is φ = 100117060710010.

The previous prime is 200234121419951. The next prime is 200234121420119. The reversal of 200234121420022 is 220024121432002.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×2002341214200222 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50058530355004 + ... + 50058530355007.

It is an arithmetic number, because the mean of its divisors is an integer number (75087795532509).

Almost surely, 2200234121420022 is an apocalyptic number.

200234121420022 is a deficient number, since it is larger than the sum of its proper divisors (100117060710014).

200234121420022 is a wasteful number, since it uses less digits than its factorization.

200234121420022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100117060710013.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 200234121420022 its reverse (220024121432002), we get a palindrome (420258242852024).

The spelling of 200234121420022 in words is "two hundred trillion, two hundred thirty-four billion, one hundred twenty-one million, four hundred twenty thousand, twenty-two".

Divisors: 1 2 100117060710011 200234121420022