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200234314011341 = 412133485848777
BaseRepresentation
bin101101100001110010101111…
…001010001001001011001101
3222020222012202121210010110202
4231201302233022021023031
5202221114333341330331
61545510212435543245
760114310651461101
oct5541625712111315
9866865677703422
10200234314011341
1158889994186105
121a55a90275ab25
138796026659c7c
14376356d083901
151823849c3cecb
hexb61caf2892cd

200234314011341 has 4 divisors (see below), whose sum is σ = 200234800272252. Its totient is φ = 200233827750432.

The previous prime is 200234314011323. The next prime is 200234314011401. The reversal of 200234314011341 is 143110413432002.

200234314011341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 131107560948841 + 69126753062500 = 11450221^2 + 8314250^2 .

It is a cyclic number.

It is not a de Polignac number, because 200234314011341 - 222 = 200234309817037 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200234317011341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 242512256 + ... + 243336521.

It is an arithmetic number, because the mean of its divisors is an integer number (50058700068063).

Almost surely, 2200234314011341 is an apocalyptic number.

It is an amenable number.

200234314011341 is a deficient number, since it is larger than the sum of its proper divisors (486260911).

200234314011341 is an equidigital number, since it uses as much as digits as its factorization.

200234314011341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 486260910.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 200234314011341 its reverse (143110413432002), we get a palindrome (343344727443343).

The spelling of 200234314011341 in words is "two hundred trillion, two hundred thirty-four billion, three hundred fourteen million, eleven thousand, three hundred forty-one".

Divisors: 1 412133 485848777 200234314011341