Base | Representation |
---|---|
bin | 1001000110110001101010… |
… | …00010010010010000100011 |
3 | 2121220021111220010002212021 |
4 | 10203120311002102100203 |
5 | 10111033201443403400 |
6 | 110330524451042311 |
7 | 4134455030641315 |
oct | 443306502222043 |
9 | 77807456102767 |
10 | 20024027325475 |
11 | 6420162444318 |
12 | 22b495a2a0397 |
13 | b233471598a4 |
14 | 4d324d36b7b5 |
15 | 24ad0e47371a |
hex | 123635092423 |
20024027325475 has 48 divisors (see below), whose sum is σ = 26245476928000. Its totient is φ = 15112953820800.
The previous prime is 20024027325473. The next prime is 20024027325479. The reversal of 20024027325475 is 57452372042002.
It is not a de Polignac number, because 20024027325475 - 21 = 20024027325473 is a prime.
It is not an unprimeable number, because it can be changed into a prime (20024027325473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 280456081 + ... + 280527469.
Almost surely, 220024027325475 is an apocalyptic number.
20024027325475 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
20024027325475 is a deficient number, since it is larger than the sum of its proper divisors (6221449602525).
20024027325475 is a wasteful number, since it uses less digits than its factorization.
20024027325475 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 73868 (or 73863 counting only the distinct ones).
The product of its (nonzero) digits is 940800, while the sum is 43.
Adding to 20024027325475 its reverse (57452372042002), we get a palindrome (77476399367477).
The spelling of 20024027325475 in words is "twenty trillion, twenty-four billion, twenty-seven million, three hundred twenty-five thousand, four hundred seventy-five".
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