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20024030300003 = 26097674982867
BaseRepresentation
bin1001000110110001101010…
…01101101000011101100011
32121220021112002201020010222
410203120311031220131203
510111033203224100003
6110330525034513255
74134455065140362
oct443306515503543
977807462636128
1020024030300003
116420164096104
1222b495b29582b
13b2334795b772
144d324d9037d9
1524ad0e85ec38
hex123635368763

20024030300003 has 4 divisors (see below), whose sum is σ = 20031705285480. Its totient is φ = 20016355314528.

The previous prime is 20024030299979. The next prime is 20024030300023. The reversal of 20024030300003 is 30000303042002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20024030300003 - 28 = 20024030299747 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20024030300023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3837488825 + ... + 3837494042.

It is an arithmetic number, because the mean of its divisors is an integer number (5007926321370).

Almost surely, 220024030300003 is an apocalyptic number.

20024030300003 is a deficient number, since it is larger than the sum of its proper divisors (7674985477).

20024030300003 is an equidigital number, since it uses as much as digits as its factorization.

20024030300003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7674985476.

The product of its (nonzero) digits is 432, while the sum is 17.

Adding to 20024030300003 its reverse (30000303042002), we get a palindrome (50024333342005).

The spelling of 20024030300003 in words is "twenty trillion, twenty-four billion, thirty million, three hundred thousand, three".

Divisors: 1 2609 7674982867 20024030300003