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200240431132123 is a prime number
BaseRepresentation
bin101101100001111000011011…
…110001000110110111011011
3222020222210112221020001122201
4231201320123301012313123
5202221214400332211443
61545513103435031031
760114615360236344
oct5541703361066733
9866883487201581
10200240431132123
1158891543131528
121a55bb2b29b477
13879678ca82275
14376398d65d0cb
151823aa6cad34d
hexb61e1bc46ddb

200240431132123 has 2 divisors, whose sum is σ = 200240431132124. Its totient is φ = 200240431132122.

The previous prime is 200240431132121. The next prime is 200240431132139. The reversal of 200240431132123 is 321231134042002.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 200240431132123 - 21 = 200240431132121 is a prime.

Together with 200240431132121, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 200240431132091 and 200240431132100.

It is not a weakly prime, because it can be changed into another prime (200240431132121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100120215566061 + 100120215566062.

It is an arithmetic number, because the mean of its divisors is an integer number (100120215566062).

Almost surely, 2200240431132123 is an apocalyptic number.

200240431132123 is a deficient number, since it is larger than the sum of its proper divisors (1).

200240431132123 is an equidigital number, since it uses as much as digits as its factorization.

200240431132123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 200240431132123 its reverse (321231134042002), we get a palindrome (521471565174125).

The spelling of 200240431132123 in words is "two hundred trillion, two hundred forty billion, four hundred thirty-one million, one hundred thirty-two thousand, one hundred twenty-three".