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20024206331477 is a prime number
BaseRepresentation
bin1001000110110001111111…
…01101001000111001010101
32121220021222100221112221012
410203120333231020321111
510111034033310101402
6110330554323502005
74134462333316565
oct443307755107125
977807870845835
1020024206331477
116420244498167
1222b49aa227905
13b233752731ba
144d3269046da5
1524ad20032452
hex12363fb48e55

20024206331477 has 2 divisors, whose sum is σ = 20024206331478. Its totient is φ = 20024206331476.

The previous prime is 20024206331401. The next prime is 20024206331491. The reversal of 20024206331477 is 77413360242002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11534622742756 + 8489583588721 = 3396266^2 + 2913689^2 .

It is a cyclic number.

It is not a de Polignac number, because 20024206331477 - 240 = 18924694703701 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20024206331977) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10012103165738 + 10012103165739.

It is an arithmetic number, because the mean of its divisors is an integer number (10012103165739).

Almost surely, 220024206331477 is an apocalyptic number.

It is an amenable number.

20024206331477 is a deficient number, since it is larger than the sum of its proper divisors (1).

20024206331477 is an equidigital number, since it uses as much as digits as its factorization.

20024206331477 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 338688, while the sum is 41.

Adding to 20024206331477 its reverse (77413360242002), we get a palindrome (97437566573479).

The spelling of 20024206331477 in words is "twenty trillion, twenty-four billion, two hundred six million, three hundred thirty-one thousand, four hundred seventy-seven".