Base | Representation |
---|---|
bin | 11101001000111010111… |
… | …011010111101100100101 |
3 | 21002102122201112112102020 |
4 | 131020322323113230211 |
5 | 230302001002331041 |
6 | 4131524303333353 |
7 | 264446262036066 |
oct | 35107273275445 |
9 | 7072581475366 |
10 | 2002443402021 |
11 | 7022601079a7 |
12 | 2841062b1259 |
13 | 116aa283819a |
14 | 6ccc11aa56d |
15 | 3714c778866 |
hex | 1d23aed7b25 |
2002443402021 has 8 divisors (see below), whose sum is σ = 2669932023264. Its totient is φ = 1334958524400.
The previous prime is 2002443402013. The next prime is 2002443402041. The reversal of 2002443402021 is 1202043442002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2002443402021 - 23 = 2002443402013 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2002443401982 and 2002443402000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2002443402041) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 741846 + ... + 2134296.
It is an arithmetic number, because the mean of its divisors is an integer number (333741502908).
Almost surely, 22002443402021 is an apocalyptic number.
It is an amenable number.
2002443402021 is a deficient number, since it is larger than the sum of its proper divisors (667488621243).
2002443402021 is a wasteful number, since it uses less digits than its factorization.
2002443402021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1871811.
The product of its (nonzero) digits is 3072, while the sum is 24.
Adding to 2002443402021 its reverse (1202043442002), we get a palindrome (3204486844023).
The spelling of 2002443402021 in words is "two trillion, two billion, four hundred forty-three million, four hundred two thousand, twenty-one".
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