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20024667413 = 38767516539
BaseRepresentation
bin10010101001100100…
…000010110100010101
31220200112221111120122
4102221210002310111
5312002303324123
613111010041325
71306141602362
oct225144026425
956615844518
1020024667413
118546448013
123a6a279245
131b7183363a
14d7d6a7469
157c2edebc8
hex4a9902d15

20024667413 has 4 divisors (see below), whose sum is σ = 20025222720. Its totient is φ = 20024112108.

The previous prime is 20024667401. The next prime is 20024667427. The reversal of 20024667413 is 31476642002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20024667413 is a prime.

It is a super-2 number, since 2×200246674132 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20024667493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219503 + ... + 297036.

It is an arithmetic number, because the mean of its divisors is an integer number (5006305680).

Almost surely, 220024667413 is an apocalyptic number.

It is an amenable number.

20024667413 is a deficient number, since it is larger than the sum of its proper divisors (555307).

20024667413 is an equidigital number, since it uses as much as digits as its factorization.

20024667413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 555306.

The product of its (nonzero) digits is 48384, while the sum is 35.

The spelling of 20024667413 in words is "twenty billion, twenty-four million, six hundred sixty-seven thousand, four hundred thirteen".

Divisors: 1 38767 516539 20024667413