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20030111132302 = 297937310225987
BaseRepresentation
bin1001000110111100111111…
…01010001010101010001110
32121220212012212212111220001
410203132133222022222032
510111133131422213202
6110333412300114514
74135061553306415
oct443363752125216
977825185774801
1020030111132302
1164227a4606447
1222b5b77835a3a
13b23aa66b969b
144d366935447c
1524b068612d87
hex12379fa8aa8e

20030111132302 has 8 divisors (see below), whose sum is σ = 30045200314536. Its totient is φ = 10015044360792.

The previous prime is 20030111132279. The next prime is 20030111132329. The reversal of 20030111132302 is 20323111103002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a self number, because there is not a number n which added to its sum of digits gives 20030111132302.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3154248 + ... + 7071739.

It is an arithmetic number, because the mean of its divisors is an integer number (3755650039317).

Almost surely, 220030111132302 is an apocalyptic number.

20030111132302 is a deficient number, since it is larger than the sum of its proper divisors (10015089182234).

20030111132302 is a wasteful number, since it uses less digits than its factorization.

20030111132302 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11205362.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 20030111132302 its reverse (20323111103002), we get a palindrome (40353222235304).

It can be divided in two parts, 2003011 and 1132302, that added together give a palindrome (3135313).

The spelling of 20030111132302 in words is "twenty trillion, thirty billion, one hundred eleven million, one hundred thirty-two thousand, three hundred two".

Divisors: 1 2 979373 1958746 10225987 20451974 10015055566151 20030111132302