Search a number
-
+
20030301211 = 129715443563
BaseRepresentation
bin10010101001111001…
…100010010000011011
31220200221112201200211
4102221321202100123
5312010224114321
613111330511551
71306240515424
oct225171422033
956627481624
1020030301211
118549645848
123a701355b7
131b72a56a4b
14d8033264b
157c37540e1
hex4a9e6241b

20030301211 has 4 divisors (see below), whose sum is σ = 20045746072. Its totient is φ = 20014856352.

The previous prime is 20030301209. The next prime is 20030301227. The reversal of 20030301211 is 11210303002.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11210303002 = 25605151501.

It is a cyclic number.

It is not a de Polignac number, because 20030301211 - 21 = 20030301209 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20030301191 and 20030301200.

It is not an unprimeable number, because it can be changed into a prime (20030301271) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7720485 + ... + 7723078.

It is an arithmetic number, because the mean of its divisors is an integer number (5011436518).

Almost surely, 220030301211 is an apocalyptic number.

20030301211 is a deficient number, since it is larger than the sum of its proper divisors (15444861).

20030301211 is a wasteful number, since it uses less digits than its factorization.

20030301211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15444860.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 20030301211 its reverse (11210303002), we get a palindrome (31240604213).

The spelling of 20030301211 in words is "twenty billion, thirty million, three hundred one thousand, two hundred eleven".

Divisors: 1 1297 15443563 20030301211