Base | Representation |
---|---|
bin | 101101100010110010111001… |
… | …000110100001111010111111 |
3 | 222021012210120102111211110111 |
4 | 231202302321012201322333 |
5 | 202223231423240004043 |
6 | 1550002004144250451 |
7 | 60122300013412633 |
oct | 5542627106417277 |
9 | 867183512454414 |
10 | 200303200313023 |
11 | 58906123757145 |
12 | 1a570128610a27 |
13 | 879c684138922 |
14 | 3766a25bd2dc3 |
15 | 182552c6ae09d |
hex | b62cb91a1ebf |
200303200313023 has 2 divisors, whose sum is σ = 200303200313024. Its totient is φ = 200303200313022.
The previous prime is 200303200313009. The next prime is 200303200313033. The reversal of 200303200313023 is 320313002303002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200303200313023 - 241 = 198104177057471 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 200303200312985 and 200303200313003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200303200313003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100151600156511 + 100151600156512.
It is an arithmetic number, because the mean of its divisors is an integer number (100151600156512).
Almost surely, 2200303200313023 is an apocalyptic number.
200303200313023 is a deficient number, since it is larger than the sum of its proper divisors (1).
200303200313023 is an equidigital number, since it uses as much as digits as its factorization.
200303200313023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 22.
Adding to 200303200313023 its reverse (320313002303002), we get a palindrome (520616202616025).
The spelling of 200303200313023 in words is "two hundred trillion, three hundred three billion, two hundred million, three hundred thirteen thousand, twenty-three".
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