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20030411033341 is a prime number
BaseRepresentation
bin1001000110111101100011…
…00010001100101011111101
32121220212222210012001202221
410203132301202030223331
510111134240211031331
6110333502132045341
74135102154364442
oct443366142145375
977825883161687
1020030411033341
116422938922545
1222b6040163851
13b23b23881417
144d36970dd9c9
1524b084b02711
hex1237b188cafd

20030411033341 has 2 divisors, whose sum is σ = 20030411033342. Its totient is φ = 20030411033340.

The previous prime is 20030411033273. The next prime is 20030411033351. The reversal of 20030411033341 is 14333011403002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19623393828900 + 407017204441 = 4429830^2 + 637979^2 .

It is a cyclic number.

It is not a de Polignac number, because 20030411033341 - 241 = 17831387777789 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20030411033351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10015205516670 + 10015205516671.

It is an arithmetic number, because the mean of its divisors is an integer number (10015205516671).

Almost surely, 220030411033341 is an apocalyptic number.

It is an amenable number.

20030411033341 is a deficient number, since it is larger than the sum of its proper divisors (1).

20030411033341 is an equidigital number, since it uses as much as digits as its factorization.

20030411033341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 20030411033341 its reverse (14333011403002), we get a palindrome (34363422436343).

The spelling of 20030411033341 in words is "twenty trillion, thirty billion, four hundred eleven million, thirty-three thousand, three hundred forty-one".