Base | Representation |
---|---|
bin | 1001000110111101100011… |
… | …00011100110111011111010 |
3 | 2121220212222210212211212002 |
4 | 10203132301203212323322 |
5 | 10111134240304344002 |
6 | 110333502144021002 |
7 | 4135102160464250 |
oct | 443366143467372 |
9 | 77825883784762 |
10 | 20030411403002 |
11 | 6422939055250 |
12 | 22b6040301762 |
13 | b23b23980760 |
14 | 4d36971985d0 |
15 | 24b084b77002 |
hex | 1237b18e6efa |
20030411403002 has 32 divisors (see below), whose sum is σ = 40340968424064. Its totient is φ = 7203744360000.
The previous prime is 20030411402959. The next prime is 20030411403017.
20030411403002 is nontrivially palindromic in base 10.
It is a super-3 number, since 3×200304114030023 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5002598249 + ... + 5002602252.
It is an arithmetic number, because the mean of its divisors is an integer number (1260655263252).
Almost surely, 220030411403002 is an apocalyptic number.
20030411403002 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
20030411403002 is an abundant number, since it is smaller than the sum of its proper divisors (20310557021062).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
20030411403002 is a wasteful number, since it uses less digits than its factorization.
20030411403002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10005200534.
The product of its (nonzero) digits is 576, while the sum is 20.
It can be divided in two parts, 2003041 and 1403002, that added together give a palindrome (3406043).
The spelling of 20030411403002 in words is "twenty trillion, thirty billion, four hundred eleven million, four hundred three thousand, two".
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