Base | Representation |
---|---|
bin | 1011101010001101101… |
… | …0000000101000000011 |
3 | 201011000221121022201202 |
4 | 2322203122000220003 |
5 | 11240213330001011 |
6 | 232004322251415 |
7 | 20320603623323 |
oct | 2724332005003 |
9 | 634027538652 |
10 | 200310000131 |
11 | 77a5085595a |
12 | 329a34b6b6b |
13 | 15b7360b8c7 |
14 | 99a3339283 |
15 | 53257ab23b |
hex | 2ea3680a03 |
200310000131 has 2 divisors, whose sum is σ = 200310000132. Its totient is φ = 200310000130.
The previous prime is 200310000103. The next prime is 200310000203. The reversal of 200310000131 is 131000013002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200310000131 - 226 = 200242891267 is a prime.
It is a super-2 number, since 2×2003100001312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (200310008131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100155000065 + 100155000066.
It is an arithmetic number, because the mean of its divisors is an integer number (100155000066).
Almost surely, 2200310000131 is an apocalyptic number.
200310000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
200310000131 is an equidigital number, since it uses as much as digits as its factorization.
200310000131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 11.
Adding to 200310000131 its reverse (131000013002), we get a palindrome (331310013133).
The spelling of 200310000131 in words is "two hundred billion, three hundred ten million, one hundred thirty-one", and thus it is an aban number.
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