Search a number
-
+
2003103123113 = 6729897061539
BaseRepresentation
bin11101001001100010010…
…000000000011010101001
321002111100200220211121202
4131021202100000122221
5230304323344414423
64132113551413545
7264501522421151
oct35114220003251
97074320824552
102003103123113
11702569546144
1228426b2242b5
13116b79413ab1
146cd44a5b761
153718a641728
hex1d2624006a9

2003103123113 has 4 divisors (see below), whose sum is σ = 2033000184720. Its totient is φ = 1973206061508.

The previous prime is 2003103123103. The next prime is 2003103123179. The reversal of 2003103123113 is 3113213013002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2003103123113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2003103123103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14948530703 + ... + 14948530836.

It is an arithmetic number, because the mean of its divisors is an integer number (508250046180).

Almost surely, 22003103123113 is an apocalyptic number.

It is an amenable number.

2003103123113 is a deficient number, since it is larger than the sum of its proper divisors (29897061607).

2003103123113 is an equidigital number, since it uses as much as digits as its factorization.

2003103123113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29897061606.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 2003103123113 its reverse (3113213013002), we get a palindrome (5116316136115).

The spelling of 2003103123113 in words is "two trillion, three billion, one hundred three million, one hundred twenty-three thousand, one hundred thirteen".

Divisors: 1 67 29897061539 2003103123113