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2003110203121 = 2398381214239
BaseRepresentation
bin11101001001100010101…
…011000000111011110001
321002111101012020112120021
4131021202223000323301
5230304332202444441
64132114403243441
7264501636536446
oct35114253007361
97074335215507
102003110203121
11702572541495
12284271679581
13116b7aa22551
146cd459819cd
153718b08e3d1
hex1d262ac0ef1

2003110203121 has 4 divisors (see below), whose sum is σ = 2011491417600. Its totient is φ = 1994728988644.

The previous prime is 2003110203079. The next prime is 2003110203131. The reversal of 2003110203121 is 1213020113002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2003110203121 - 27 = 2003110202993 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2003110203095 and 2003110203104.

It is not an unprimeable number, because it can be changed into a prime (2003110203131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4190606881 + ... + 4190607358.

It is an arithmetic number, because the mean of its divisors is an integer number (502872854400).

Almost surely, 22003110203121 is an apocalyptic number.

It is an amenable number.

2003110203121 is a deficient number, since it is larger than the sum of its proper divisors (8381214479).

2003110203121 is an equidigital number, since it uses as much as digits as its factorization.

2003110203121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8381214478.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 2003110203121 its reverse (1213020113002), we get a palindrome (3216130316123).

The spelling of 2003110203121 in words is "two trillion, three billion, one hundred ten million, two hundred three thousand, one hundred twenty-one".

Divisors: 1 239 8381214239 2003110203121