Base | Representation |
---|---|
bin | 11101001001100010101… |
… | …110100001000100101111 |
3 | 21002111101020222011221011 |
4 | 131021202232201010233 |
5 | 230304332421334244 |
6 | 4132114435050051 |
7 | 264501650412166 |
oct | 35114256410457 |
9 | 7074336864834 |
10 | 2003111121199 |
11 | 702573009231 |
12 | 284271a40927 |
13 | 116b7ac843a6 |
14 | 6cd45b403dd |
15 | 3718b1c1434 |
hex | 1d262ba112f |
2003111121199 has 2 divisors, whose sum is σ = 2003111121200. Its totient is φ = 2003111121198.
The previous prime is 2003111121191. The next prime is 2003111121241. The reversal of 2003111121199 is 9911211113002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2003111121199 - 23 = 2003111121191 is a prime.
It is a super-2 number, since 2×20031111211992 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2003111121199.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2003111121191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001555560599 + 1001555560600.
It is an arithmetic number, because the mean of its divisors is an integer number (1001555560600).
Almost surely, 22003111121199 is an apocalyptic number.
2003111121199 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003111121199 is an equidigital number, since it uses as much as digits as its factorization.
2003111121199 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 31.
The spelling of 2003111121199 in words is "two trillion, three billion, one hundred eleven million, one hundred twenty-one thousand, one hundred ninety-nine".
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