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2003112212003 = 71972731450573
BaseRepresentation
bin11101001001100010110…
…010101011011000100011
321002111101100000121020022
4131021202302223120203
5230304333211241003
64132114514304055
7264501662604320
oct35114262533043
97074340017208
102003112212003
11702573693821
1228427228802b
13116b7b276a36
146cd45d45b47
153718b339738
hex1d262cab623

2003112212003 has 8 divisors (see below), whose sum is σ = 2289284282208. Its totient is φ = 1716943437504.

The previous prime is 2003112211999. The next prime is 2003112212021. The reversal of 2003112212003 is 3002122113002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2003112212003 - 22 = 2003112211999 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2003112212083) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 655625 + ... + 2106197.

It is an arithmetic number, because the mean of its divisors is an integer number (286160535276).

Almost surely, 22003112212003 is an apocalyptic number.

2003112212003 is a deficient number, since it is larger than the sum of its proper divisors (286172070205).

2003112212003 is a wasteful number, since it uses less digits than its factorization.

2003112212003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1647853.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 2003112212003 its reverse (3002122113002), we get a palindrome (5005234325005).

Subtracting 2003112212003 from its reverse (3002122113002), we obtain a palindrome (999009900999).

The spelling of 2003112212003 in words is "two trillion, three billion, one hundred twelve million, two hundred twelve thousand, three".

Divisors: 1 7 197273 1380911 1450573 10154011 286158887429 2003112212003