Base | Representation |
---|---|
bin | 11101001001100010110… |
… | …011000000111001101111 |
3 | 21002111101100012002010202 |
4 | 131021202303000321233 |
5 | 230304333222101033 |
6 | 4132114520224115 |
7 | 264501663422303 |
oct | 35114263007157 |
9 | 7074340162122 |
10 | 2003112300143 |
11 | 702573743a69 |
12 | 28427230b03b |
13 | 116b7b2a7ba6 |
14 | 6cd45d69d03 |
15 | 3718b3558e8 |
hex | 1d262cc0e6f |
2003112300143 has 2 divisors, whose sum is σ = 2003112300144. Its totient is φ = 2003112300142.
The previous prime is 2003112300121. The next prime is 2003112300149. The reversal of 2003112300143 is 3410032113002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2003112300143 - 212 = 2003112296047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2003112300149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001556150071 + 1001556150072.
It is an arithmetic number, because the mean of its divisors is an integer number (1001556150072).
Almost surely, 22003112300143 is an apocalyptic number.
2003112300143 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003112300143 is an equidigital number, since it uses as much as digits as its factorization.
2003112300143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 2003112300143 its reverse (3410032113002), we get a palindrome (5413144413145).
The spelling of 2003112300143 in words is "two trillion, three billion, one hundred twelve million, three hundred thousand, one hundred forty-three".
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