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200311341389 is a prime number
BaseRepresentation
bin1011101010001101111…
…1001000000101001101
3201011001001010110120222
42322203133020011031
511240214200411024
6232004411121125
720320621210565
oct2724337100515
9634031113528
10200311341389
1177a51591635
12329a3a431a5
1315b7398b253
1499a35a7da5
15532597385e
hex2ea37c814d

200311341389 has 2 divisors, whose sum is σ = 200311341390. Its totient is φ = 200311341388.

The previous prime is 200311341383. The next prime is 200311341437. The reversal of 200311341389 is 983143113002.

200311341389 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 169505124100 + 30806217289 = 411710^2 + 175517^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200311341389 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200311341383) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100155670694 + 100155670695.

It is an arithmetic number, because the mean of its divisors is an integer number (100155670695).

Almost surely, 2200311341389 is an apocalyptic number.

It is an amenable number.

200311341389 is a deficient number, since it is larger than the sum of its proper divisors (1).

200311341389 is an equidigital number, since it uses as much as digits as its factorization.

200311341389 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 200311341389 in words is "two hundred billion, three hundred eleven million, three hundred forty-one thousand, three hundred eighty-nine".