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2003121033132 = 223211791122051
BaseRepresentation
bin11101001001100011010…
…100010100111110101100
321002111101221121202112210
4131021203110110332230
5230304342441030012
64132115431330420
7264502130564022
oct35114324247654
97074357552483
102003121033132
1170257866920a
12284275220a10
13116b80044b3b
146cd471a0712
153718becd23c
hex1d263514fac

2003121033132 has 24 divisors (see below), whose sum is σ = 4696100500672. Its totient is φ = 664542522000.

The previous prime is 2003121033079. The next prime is 2003121033161. The reversal of 2003121033132 is 2313301213002.

It is a super-2 number, since 2×20031210331322 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2003121033099 and 2003121033108.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 395558494 + ... + 395563557.

Almost surely, 22003121033132 is an apocalyptic number.

It is an amenable number.

2003121033132 is an abundant number, since it is smaller than the sum of its proper divisors (2692979467540).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2003121033132 is a wasteful number, since it uses less digits than its factorization.

2003121033132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 791122269 (or 791122267 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 2003121033132 its reverse (2313301213002), we get a palindrome (4316422246134).

The spelling of 2003121033132 in words is "two trillion, three billion, one hundred twenty-one million, thirty-three thousand, one hundred thirty-two".

Divisors: 1 2 3 4 6 12 211 422 633 844 1266 2532 791122051 1582244102 2373366153 3164488204 4746732306 9493464612 166926752761 333853505522 500780258283 667707011044 1001560516566 2003121033132