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200312110131132 = 22331538473414331
BaseRepresentation
bin101101100010111011001100…
…001010110010011110111100
3222021020122120100220111011210
4231202323030022302132330
5202223403200143144012
61550010040224444420
760123033552543006
oct5542731412623674
9867218510814153
10200312110131132
115890998605238a
121a5719b4479710
1387a047400224c
14376722d251376
15182589e9c523c
hexb62ecc2b27bc

200312110131132 has 24 divisors (see below), whose sum is σ = 482472179241472. Its totient is φ = 64616809719600.

The previous prime is 200312110131113. The next prime is 200312110131149. The reversal of 200312110131132 is 231131011213002.

It is a junction number, because it is equal to n+sod(n) for n = 200312110131099 and 200312110131108.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 269236706794 + ... + 269236707537.

Almost surely, 2200312110131132 is an apocalyptic number.

It is an amenable number.

200312110131132 is an abundant number, since it is smaller than the sum of its proper divisors (282160069110340).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

200312110131132 is a wasteful number, since it uses less digits than its factorization.

200312110131132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 538473414369 (or 538473414367 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 200312110131132 its reverse (231131011213002), we get a palindrome (431443121344134).

The spelling of 200312110131132 in words is "two hundred trillion, three hundred twelve billion, one hundred ten million, one hundred thirty-one thousand, one hundred thirty-two".

Divisors: 1 2 3 4 6 12 31 62 93 124 186 372 538473414331 1076946828662 1615420242993 2153893657324 3230840485986 6461680971972 16692675844261 33385351688522 50078027532783 66770703377044 100156055065566 200312110131132