Base | Representation |
---|---|
bin | 101101100010111011001100… |
… | …001010110010111110001011 |
3 | 222021020122120100220120220211 |
4 | 231202323030022302332023 |
5 | 202223403200143230011 |
6 | 1550010040224501551 |
7 | 60123033552551563 |
oct | 5542731412627613 |
9 | 867218510816824 |
10 | 200312110133131 |
11 | 58909986053937 |
12 | 1a5719b447a8b7 |
13 | 87a0474003129 |
14 | 376722d251da3 |
15 | 182589e9c5b21 |
hex | b62ecc2b2f8b |
200312110133131 has 2 divisors, whose sum is σ = 200312110133132. Its totient is φ = 200312110133130.
The previous prime is 200312110133117. The next prime is 200312110133183. The reversal of 200312110133131 is 131331011213002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200312110133131 - 29 = 200312110132619 is a prime.
It is a super-2 number, since 2×2003121101331312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (200312110133731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100156055066565 + 100156055066566.
It is an arithmetic number, because the mean of its divisors is an integer number (100156055066566).
Almost surely, 2200312110133131 is an apocalyptic number.
200312110133131 is a deficient number, since it is larger than the sum of its proper divisors (1).
200312110133131 is an equidigital number, since it uses as much as digits as its factorization.
200312110133131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 200312110133131 its reverse (131331011213002), we get a palindrome (331643121346133).
The spelling of 200312110133131 in words is "two hundred trillion, three hundred twelve billion, one hundred ten million, one hundred thirty-three thousand, one hundred thirty-one".
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