Base | Representation |
---|---|
bin | 101101100010111011001100… |
… | …010011001000111101001010 |
3 | 222021020122120112000201012012 |
4 | 231202323030103020331022 |
5 | 202223403201223222310 |
6 | 1550010040343415522 |
7 | 60123033610261343 |
oct | 5542731423107512 |
9 | 867218515021165 |
10 | 200312112320330 |
11 | 5890998730813a |
12 | 1a5719b51545a2 |
13 | 87a04745ba82a |
14 | 376722d6610ca |
15 | 182589eca8c05 |
hex | b62ecc4c8f4a |
200312112320330 has 16 divisors (see below), whose sum is σ = 364278934159560. Its totient is φ = 79298815598592.
The previous prime is 200312112320311. The next prime is 200312112320371. The reversal of 200312112320330 is 33023211213002.
200312112320330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 4 ways, for example, as 86838337426681 + 113473774893649 = 9318709^2 + 10652407^2 .
It is a junction number, because it is equal to n+sod(n) for n = 200312112320296 and 200312112320305.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 103253665175 + ... + 103253667114.
Almost surely, 2200312112320330 is an apocalyptic number.
200312112320330 is a deficient number, since it is larger than the sum of its proper divisors (163966821839230).
200312112320330 is a wasteful number, since it uses less digits than its factorization.
200312112320330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 206507332393.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 200312112320330 its reverse (33023211213002), we get a palindrome (233335323533332).
The spelling of 200312112320330 in words is "two hundred trillion, three hundred twelve billion, one hundred twelve million, three hundred twenty thousand, three hundred thirty".
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