Base | Representation |
---|---|
bin | 11101001001100011010… |
… | …101101111010011100111 |
3 | 21002111101222022120001201 |
4 | 131021203111233103213 |
5 | 230304343034344421 |
6 | 4132115443303331 |
7 | 264502133664463 |
oct | 35114325572347 |
9 | 7074358276051 |
10 | 2003121403111 |
11 | 7025788a1184 |
12 | 28427537ab47 |
13 | 116b8014436a |
14 | 6cd472594a3 |
15 | 3718c052b91 |
hex | 1d26356f4e7 |
2003121403111 has 48 divisors (see below), whose sum is σ = 2192910239520. Its totient is φ = 1828314270720.
The previous prime is 2003121403103. The next prime is 2003121403159. The reversal of 2003121403111 is 1113041213002.
It is not a de Polignac number, because 2003121403111 - 23 = 2003121403103 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (19).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2003121493111) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 394235091 + ... + 394240171.
It is an arithmetic number, because the mean of its divisors is an integer number (45685629990).
Almost surely, 22003121403111 is an apocalyptic number.
2003121403111 is a deficient number, since it is larger than the sum of its proper divisors (189788836409).
2003121403111 is a wasteful number, since it uses less digits than its factorization.
2003121403111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5504 (or 5485 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 2003121403111 its reverse (1113041213002), we get a palindrome (3116162616113).
The spelling of 2003121403111 in words is "two trillion, three billion, one hundred twenty-one million, four hundred three thousand, one hundred eleven".
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