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200312201113 = 1910542747427
BaseRepresentation
bin1011101010001110001…
…0011001111110011001
3201011001002202010220121
42322203202121332121
511240214410413423
6232004441353241
720320631421223
oct2724342317631
9634032663817
10200312201113
1177a52019552
12329a4198821
1315b73bcc66b
1499a374d413
155325a9345d
hex2ea3899f99

200312201113 has 4 divisors (see below), whose sum is σ = 210854948560. Its totient is φ = 189769453668.

The previous prime is 200312201069. The next prime is 200312201143. The reversal of 200312201113 is 311102213002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200312201113 - 229 = 199775330201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200312201143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5271373695 + ... + 5271373732.

It is an arithmetic number, because the mean of its divisors is an integer number (52713737140).

Almost surely, 2200312201113 is an apocalyptic number.

It is an amenable number.

200312201113 is a deficient number, since it is larger than the sum of its proper divisors (10542747447).

200312201113 is a wasteful number, since it uses less digits than its factorization.

200312201113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10542747446.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 200312201113 its reverse (311102213002), we get a palindrome (511414414115).

The spelling of 200312201113 in words is "two hundred billion, three hundred twelve million, two hundred one thousand, one hundred thirteen".

Divisors: 1 19 10542747427 200312201113