Base | Representation |
---|---|
bin | 101101100010111100000001… |
… | …010101011011010101000011 |
3 | 222021020201212112022211100012 |
4 | 231202330001111123111003 |
5 | 202223412012020043243 |
6 | 1550010304531015135 |
7 | 60123064633343162 |
oct | 5542740125332503 |
9 | 867221775284305 |
10 | 200313002112323 |
11 | 5890a2a35a8021 |
12 | 1a57200313a4ab |
13 | 87a0586a4ba79 |
14 | 37672b58c13d9 |
15 | 1825902e6ad18 |
hex | b62f0155b543 |
200313002112323 has 2 divisors, whose sum is σ = 200313002112324. Its totient is φ = 200313002112322.
The previous prime is 200313002112281. The next prime is 200313002112341. The reversal of 200313002112323 is 323211200313002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200313002112323 - 224 = 200312985335107 is a prime.
It is not a weakly prime, because it can be changed into another prime (200313002112023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100156501056161 + 100156501056162.
It is an arithmetic number, because the mean of its divisors is an integer number (100156501056162).
Almost surely, 2200313002112323 is an apocalyptic number.
200313002112323 is a deficient number, since it is larger than the sum of its proper divisors (1).
200313002112323 is an equidigital number, since it uses as much as digits as its factorization.
200313002112323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 200313002112323 its reverse (323211200313002), we get a palindrome (523524202425325).
The spelling of 200313002112323 in words is "two hundred trillion, three hundred thirteen billion, two million, one hundred twelve thousand, three hundred twenty-three".
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