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20031302013 = 36677100671
BaseRepresentation
bin10010101001111101…
…010110100101111101
31220201000102120112120
4102221331112211331
5312011003131023
613111404153153
71306252154262
oct225175264575
956630376476
1020031302013
11854a169758
123a705387b9
131b73017438
14d80513269
157c38a08e3
hex4a9f5697d

20031302013 has 4 divisors (see below), whose sum is σ = 26708402688. Its totient is φ = 13354201340.

The previous prime is 20031302009. The next prime is 20031302033. The reversal of 20031302013 is 31020313002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20031302013 - 22 = 20031302009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20031301983 and 20031302001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20031302003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3338550333 + ... + 3338550338.

It is an arithmetic number, because the mean of its divisors is an integer number (6677100672).

Almost surely, 220031302013 is an apocalyptic number.

It is an amenable number.

20031302013 is a deficient number, since it is larger than the sum of its proper divisors (6677100675).

20031302013 is an equidigital number, since it uses as much as digits as its factorization.

20031302013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6677100674.

The product of its (nonzero) digits is 108, while the sum is 15.

Adding to 20031302013 its reverse (31020313002), we get a palindrome (51051615015).

The spelling of 20031302013 in words is "twenty billion, thirty-one million, three hundred two thousand, thirteen".

Divisors: 1 3 6677100671 20031302013