Base | Representation |
---|---|
bin | 11101001001100011110… |
… | …111110110000000010001 |
3 | 21002111102121010202220001 |
4 | 131021203313312000101 |
5 | 230304402331442231 |
6 | 4132120403050001 |
7 | 264502302661543 |
oct | 35114367660021 |
9 | 7074377122801 |
10 | 2003130343441 |
11 | 702582948187 |
12 | 284278370901 |
13 | 116b81c547b6 |
14 | 6cd48505693 |
15 | 3718cc1bb61 |
hex | 1d263df6011 |
2003130343441 has 4 divisors (see below), whose sum is σ = 2120961540132. Its totient is φ = 1885299146752.
The previous prime is 2003130343429. The next prime is 2003130343453. The reversal of 2003130343441 is 1443430313002.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (2003130343429) and next prime (2003130343453).
It can be written as a sum of positive squares in 2 ways, for example, as 1682932803841 + 320197539600 = 1297279^2 + 565860^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2003130343441 is a prime.
It is a super-2 number, since 2×20031303434412 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2003130347441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58915598320 + ... + 58915598353.
It is an arithmetic number, because the mean of its divisors is an integer number (530240385033).
Almost surely, 22003130343441 is an apocalyptic number.
It is an amenable number.
2003130343441 is a deficient number, since it is larger than the sum of its proper divisors (117831196691).
2003130343441 is a wasteful number, since it uses less digits than its factorization.
2003130343441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 117831196690.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 2003130343441 its reverse (1443430313002), we get a palindrome (3446560656443).
The spelling of 2003130343441 in words is "two trillion, three billion, one hundred thirty million, three hundred forty-three thousand, four hundred forty-one".
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