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2003131322321 = 8592331934019
BaseRepresentation
bin11101001001100011111…
…011100100111111010001
321002111102122222111122212
4131021203323210333101
5230304403104303241
64132120440041505
7264502314206453
oct35114373447721
97074378874585
102003131322321
11702583456678
12284278763295
13116b8220820c
146cd486bc2d3
153718cd61beb
hex1d263ee4fd1

2003131322321 has 4 divisors (see below), whose sum is σ = 2005463257200. Its totient is φ = 2000799387444.

The previous prime is 2003131322287. The next prime is 2003131322323. The reversal of 2003131322321 is 1232231313002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2003131322321 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2003131322323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1165966151 + ... + 1165967868.

It is an arithmetic number, because the mean of its divisors is an integer number (501365814300).

Almost surely, 22003131322321 is an apocalyptic number.

It is an amenable number.

2003131322321 is a deficient number, since it is larger than the sum of its proper divisors (2331934879).

2003131322321 is an equidigital number, since it uses as much as digits as its factorization.

2003131322321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2331934878.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 2003131322321 its reverse (1232231313002), we get a palindrome (3235362635323).

The spelling of 2003131322321 in words is "two trillion, three billion, one hundred thirty-one million, three hundred twenty-two thousand, three hundred twenty-one".

Divisors: 1 859 2331934019 2003131322321