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2003144394793 is a prime number
BaseRepresentation
bin11101001001100100101…
…101011100100000101001
321002111110120120122201111
4131021210231130200221
5230304414431113133
64132122024150321
7264502533263563
oct35114455344051
97074416518644
102003144394793
1170258a875173
122842810083a1
13116b84b343c9
146cd4a322333
153718e0951cd
hex1d264b5c829

2003144394793 has 2 divisors, whose sum is σ = 2003144394794. Its totient is φ = 2003144394792.

The previous prime is 2003144394773. The next prime is 2003144394907. The reversal of 2003144394793 is 3974934413002.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1218710018304 + 784434376489 = 1103952^2 + 885683^2 .

It is a cyclic number.

It is not a de Polignac number, because 2003144394793 - 229 = 2002607523881 is a prime.

It is a super-2 number, since 2×20031443947932 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2003144394743) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001572197396 + 1001572197397.

It is an arithmetic number, because the mean of its divisors is an integer number (1001572197397).

Almost surely, 22003144394793 is an apocalyptic number.

It is an amenable number.

2003144394793 is a deficient number, since it is larger than the sum of its proper divisors (1).

2003144394793 is an equidigital number, since it uses as much as digits as its factorization.

2003144394793 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1959552, while the sum is 49.

The spelling of 2003144394793 in words is "two trillion, three billion, one hundred forty-four million, three hundred ninety-four thousand, seven hundred ninety-three".