2003200112113 has 4 divisors (see below), whose sum is σ = 2003700041280. Its totient is φ = 2002700182948.

The previous prime is 2003200112099. The next prime is 2003200112119. The reversal of 2003200112113 is 3112110023002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2003200112113 - 2²⁵ = 2003166557681 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2003200112119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 249958573 + ... + 249966586.

It is an arithmetic number, because the mean of its divisors is an integer number (500925010320).

Almost surely, 2^{2003200112113} is an apocalyptic number.

It is an amenable number.

2003200112113 is a deficient number, since it is larger than the sum of its proper divisors (499929167).

2003200112113 is an equidigital number, since it uses as much as digits as its factorization.

2003200112113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 499929166.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 2003200112113 its reverse (3112110023002), we get a palindrome (5115310135115).

The spelling of 2003200112113 in words is "two trillion, three billion, two hundred million, one hundred twelve thousand, one hundred thirteen".