20032012310231 has 4 divisors (see below), whose sum is σ = 20035165474512. Its totient is φ = 20028859145952.

The previous prime is 20032012310227. The next prime is 20032012310237. The reversal of 20032012310231 is 13201321023002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20032012310231 - 2² = 20032012310227 is a prime.

It is a super-3 number, since 3×20032012310231³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20032012310237) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1576572611 + ... + 1576585316.

It is an arithmetic number, because the mean of its divisors is an integer number (5008791368628).

Almost surely, 2^{20032012310231} is an apocalyptic number.

20032012310231 is a deficient number, since it is larger than the sum of its proper divisors (3153164281).

20032012310231 is an equidigital number, since it uses as much as digits as its factorization.

20032012310231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3153164280.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 20032012310231 its reverse (13201321023002), we get a palindrome (33233333333233).

The spelling of 20032012310231 in words is "twenty trillion, thirty-two billion, twelve million, three hundred ten thousand, two hundred thirty-one".