2003201340141 has 4 divisors (see below), whose sum is σ = 2670935120192. Its totient is φ = 1335467560092.

The previous prime is 2003201340067. The next prime is 2003201340169. The reversal of 2003201340141 is 1410431023002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2003201340141 - 2²⁹ = 2002664469229 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2003201340181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 333866890021 + ... + 333866890026.

It is an arithmetic number, because the mean of its divisors is an integer number (667733780048).

Almost surely, 2^{2003201340141} is an apocalyptic number.

It is an amenable number.

2003201340141 is a deficient number, since it is larger than the sum of its proper divisors (667733780051).

2003201340141 is an equidigital number, since it uses as much as digits as its factorization.

2003201340141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 667733780050.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 2003201340141 its reverse (1410431023002), we get a palindrome (3413632363143).

The spelling of 2003201340141 in words is "two trillion, three billion, two hundred one million, three hundred forty thousand, one hundred forty-one".