Base | Representation |
---|---|
bin | 1011101010010000001… |
… | …1111110001011010011 |
3 | 201011001201022011220202 |
4 | 2322210003332023103 |
5 | 11240224134001042 |
6 | 232005354125415 |
7 | 20321066256332 |
oct | 2724403761323 |
9 | 634051264822 |
10 | 200321000147 |
11 | 77a56a89384 |
12 | 329a712086b |
13 | 15b759906a8 |
14 | 99a499dd19 |
15 | 5326730632 |
hex | 2ea40fe2d3 |
200321000147 has 2 divisors, whose sum is σ = 200321000148. Its totient is φ = 200321000146.
The previous prime is 200321000129. The next prime is 200321000153. The reversal of 200321000147 is 741000123002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200321000147 - 28 = 200320999891 is a prime.
It is not a weakly prime, because it can be changed into another prime (200321003147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100160500073 + 100160500074.
It is an arithmetic number, because the mean of its divisors is an integer number (100160500074).
Almost surely, 2200321000147 is an apocalyptic number.
200321000147 is a deficient number, since it is larger than the sum of its proper divisors (1).
200321000147 is an equidigital number, since it uses as much as digits as its factorization.
200321000147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 336, while the sum is 20.
Adding to 200321000147 its reverse (741000123002), we get a palindrome (941321123149).
The spelling of 200321000147 in words is "two hundred billion, three hundred twenty-one million, one hundred forty-seven", and thus it is an aban number.
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