Base | Representation |
---|---|
bin | 11101001001101001110… |
… | …100000011101001001111 |
3 | 21002111200112200120020101 |
4 | 131021221310003221033 |
5 | 230310103340422111 |
6 | 4132134323231531 |
7 | 264504623112421 |
oct | 35115164035117 |
9 | 7074615616211 |
10 | 2003230014031 |
11 | 702624134174 |
12 | 2842a58185a7 |
13 | 116b997b138c |
14 | 6cd5784c811 |
15 | 37196858bc1 |
hex | 1d269d03a4f |
2003230014031 has 2 divisors, whose sum is σ = 2003230014032. Its totient is φ = 2003230014030.
The previous prime is 2003230013987. The next prime is 2003230014043. The reversal of 2003230014031 is 1304100323002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2003230014031 - 211 = 2003230011983 is a prime.
It is a super-4 number, since 4×20032300140314 (a number of 50 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2003239014031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001615007015 + 1001615007016.
It is an arithmetic number, because the mean of its divisors is an integer number (1001615007016).
Almost surely, 22003230014031 is an apocalyptic number.
2003230014031 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003230014031 is an equidigital number, since it uses as much as digits as its factorization.
2003230014031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 2003230014031 its reverse (1304100323002), we get a palindrome (3307330337033).
The spelling of 2003230014031 in words is "two trillion, three billion, two hundred thirty million, fourteen thousand, thirty-one".
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