Base | Representation |
---|---|
bin | 101101100011000101010110… |
… | …101000001100011101100001 |
3 | 222021021200201220110012021112 |
4 | 231203011112220030131201 |
5 | 202224043022343430423 |
6 | 1550015043142033105 |
7 | 60123601153626014 |
oct | 5543052650143541 |
9 | 867250656405245 |
10 | 200323023030113 |
11 | 589135760a9965 |
12 | 1a573b3b118795 |
13 | 87a14c2b81319 |
14 | 376798672b37b |
15 | 1825cdcaaba78 |
hex | b63156a0c761 |
200323023030113 has 4 divisors (see below), whose sum is σ = 200323053565488. Its totient is φ = 200322992494740.
The previous prime is 200323023030047. The next prime is 200323023030157. The reversal of 200323023030113 is 311030320323002.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 200323023030113 - 218 = 200323022767969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (200323023033113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 954131 + ... + 20038872.
It is an arithmetic number, because the mean of its divisors is an integer number (50080763391372).
Almost surely, 2200323023030113 is an apocalyptic number.
It is an amenable number.
200323023030113 is a deficient number, since it is larger than the sum of its proper divisors (30535375).
200323023030113 is an equidigital number, since it uses as much as digits as its factorization.
200323023030113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30535374.
The product of its (nonzero) digits is 1944, while the sum is 23.
Adding to 200323023030113 its reverse (311030320323002), we get a palindrome (511353343353115).
The spelling of 200323023030113 in words is "two hundred trillion, three hundred twenty-three billion, twenty-three million, thirty thousand, one hundred thirteen".
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